(2x+5)(3x^2-19x+20)=0

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Solution for (2x+5)(3x^2-19x+20)=0 equation: 


Simplifying
(2x + 5)(3x2 + -19x + 20) = 0

Reorder the terms:
(5 + 2x)(3x2 + -19x + 20) = 0

Reorder the terms:
(5 + 2x)(20 + -19x + 3x2) = 0

Multiply (5 + 2x) * (20 + -19x + 3x2)
(5(20 + -19x + 3x2) + 2x * (20 + -19x + 3x2)) = 0
((20 * 5 + -19x * 5 + 3x2 * 5) + 2x * (20 + -19x + 3x2)) = 0
((100 + -95x + 15x2) + 2x * (20 + -19x + 3x2)) = 0
(100 + -95x + 15x2 + (20 * 2x + -19x * 2x + 3x2 * 2x)) = 0
(100 + -95x + 15x2 + (40x + -38x2 + 6x3)) = 0

Reorder the terms:
(100 + -95x + 40x + 15x2 + -38x2 + 6x3) = 0

Combine like terms: -95x + 40x = -55x
(100 + -55x + 15x2 + -38x2 + 6x3) = 0

Combine like terms: 15x2 + -38x2 = -23x2
(100 + -55x + -23x2 + 6x3) = 0

Solving
100 + -55x + -23x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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